Question

The above figure shows two resistors X and Y connected in series to a battery. The power dissipated for this combination is P1. When these resistors are connected in parallel to the same battery then the power dissipated is given by P2. Find out the ratio P1/P2.

Answer 1

For series total resistance is R+2R = 3R 

 P₁ = V²/3 

For parallel total Resistance is 2R/3 

P₂ = V²/(2R/3) = 3V²/2R

P₁/P₂ = 2/9